Intel® oneAPI DPC++/C++ Compiler Developer Guide and Reference

ID 767253
Date 9/08/2022
Public

A newer version of this document is available. Customers should click here to go to the newest version.

Document Table of Contents

loop_count

Specifies the iterations for a for loop.

Syntax

#pragma loop_count(n)

#pragma loop_count=n

or

#pragma loop_count(n1[, n2]...)

#pragma loop_count=n1[, n2]...

or

#pragma loop_count min(n),max(n),avg(n)

#pragma loop_count min=n, max=n, avg=n

Arguments

(n) or =n

A non-negative integer value. The compiler will attempt to iterate the next loop the number of times specified in n; however, the number of iterations is not guaranteed.

(n1[,n2]...) or = n1[,n2]...

Non-negative integer values. The compiler will attempt to iterate the next loop the number of time specified by n1 or n2, or some other unspecified number of times. This behavior allows the compiler some flexibility in attempting to unroll the loop. The number of iterations is not guaranteed.

min(n), max(n), avg(n) or min=n, max=n, avg=n

Non-negative integer values. Specify one or more in any order without duplication. The compiler insures the next loop iterates for the specified maximum, minimum, or average number (n1) of times. The specified number of iterations is guaranteed for min and max.

Description

The loop_count pragma specifies the minimum, maximum, or average number of iterations for a for loop. In addition, a list of commonly occurring values can be specified to help the compiler generate multiple versions and perform complete unrolling.

You can specify more than one pragma for a single loop; however, do not duplicate the pragma.

The loop_count pragma is supported in host code only.

Examples

Use the loop_count pragma to iterate through the loop a minimum of three, a maximum of ten, and average of five times:

#include <stdio.h> 
int i; 
int mysum(int start, int end, int a) {
  int iret=0; 
  #pragma loop_count min(3), max(10), avg(5)
    for (i=start;i<=end;i++)
    iret += a;
    return iret; 
} 

int main() {
  int t;
  t = mysum(1, 10, 3);
  printf("t1=%d\r\n",t);
  t = mysum(2, 6, 2);
  printf("t2=%d\r\n",t);
  t = mysum(5, 12, 1);
  printf("t3=%d\r\n",t); 
}